设数列{An}前n项和Sn,且(3-m)Sn+2mAn=m+3,m常数,且m不等于-3 (1)求证{An}等比(2)若数列{An}公比q=f(m),数列{bn}满足b1=a1.bn=3/2*f(b(n-1)),求证{1/bn}为等差数列,并求bn通项公式

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设数列{An}前n项和Sn,且(3-m)Sn+2mAn=m+3,m常数,且m不等于-3 (1)求证{An}等比(2)若数列{An}公比q=f(m),数列{bn}满足b1=a1.bn=3/2*f(b(n-1)),求证{1/bn}为等差数列,并求bn通项公式

设数列{An}前n项和Sn,且(3-m)Sn+2mAn=m+3,m常数,且m不等于-3 (1)求证{An}等比(2)若数列{An}公比q=f(m),数列{bn}满足b1=a1.bn=3/2*f(b(n-1)),求证{1/bn}为等差数列,并求bn通项公式
设数列{An}前n项和Sn,且(3-m)Sn+2mAn=m+3,m常数,且m不等于-3 (1)求证{An}等比
(2)若数列{An}公比q=f(m),数列{bn}满足b1=a1.bn=3/2*f(b(n-1)),求证{1/bn}为等差数列,并求bn通项公式

设数列{An}前n项和Sn,且(3-m)Sn+2mAn=m+3,m常数,且m不等于-3 (1)求证{An}等比(2)若数列{An}公比q=f(m),数列{bn}满足b1=a1.bn=3/2*f(b(n-1)),求证{1/bn}为等差数列,并求bn通项公式
1.(3-m)S(n-1)+2mA(n-1)=m+3
相减 (m+3)An=2m/(m+3)A(n-1)
2.q=2m/(m+3) bn=3b(n-1)/(b(n-1)+3)
1/bn=1/3+1/b(n-1)
b1=a1=1
1/bn=1+(n-1)/3=(n-2)/3
bn=3/(n-2)
LZ验算下 不知是否有计算错误--

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