xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1

来源：学生作业帮助网 编辑：作业帮 时间：2024/04/28 02:58:27
xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1

xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1
xy²/(x²y-y) × x²/(x²+x)=
(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=
化简求植
x²-1/(x²-x-2)除以x/2x-4,其中x=1/2
[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1

xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1
xy²/(x²y-y) × x²/(x²+x)=xy/(x²-1 ) × x/(x+1 ) =x²y/[(x+1)² × (x-1)]
(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=x-3/x-5 × 2(x-5)/(x-3)² =2/(x-3)
x²-1/(x²-x-2)除以x/2x-4,=(x+1)(x-1)/(x-2)(x+1) × 2(x-2)/x=2(x-1)/x,代入x=1/2得-2
[x-x/(x+1)]除以[x/(2x-4)] =x²/x+1 × 2(x-2)/x=2x(x-2)/(x+1)其中x=√2+1,得2-√2

6xy²-9x²y-y²因式分解 0.5x²+xy+0.5y² 因式分解：x²-xy-12y² 4x²y-xy² -9x²-y²+6xy x²-2xy+y²-9 若x²+xy-2y²=0,则x²+3xy+y²/x²+y² x²+xy-2y²=0则x²+3xy+y²/x²+y² 因式分解 x²-2xy+y²-z² x²y²-x²y-xy²+x+y-1因式分解 已知x²y²+x²+y²=10xy-16 求x,y 计算：4xy²-3x²y-{3x²y-[2xy²-4x²y+2(x²y-2xy²)]急 （x²+y²)²-x²y²=(x²+y²)²-(xy)²=(x²+y²+xy)(x²+y²-xy)=(x+y)²(x-y)²-xy+xy=(x+y)²(x-y)² x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy 计算x²-x/x²×x/1-x和x²-4y²/x²+2xy+y²÷x+2y/x²+xy 因式分解 x²-XY-2y²-X-Y x²+xy-2y²-x+7y-6 x³y³-x²y²-xy+1