作业帮y=2sin^2x-sinxcosx+3cos^2x求最小正周期,单调增区间,在[0,π/2]上的值域
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/04 19:55:30
![y=2sin^2x-sinxcosx+3cos^2x求最小正周期,单调增区间,在[0,π/2]上的值域](/uploads/image/z/3938802-42-2.jpg?t=y%3D2sin%5E2x-sinxcosx%2B3cos%5E2x%E6%B1%82%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%2C%E5%8D%95%E8%B0%83%E5%A2%9E%E5%8C%BA%E9%97%B4%2C%E5%9C%A8%5B0%2C%CF%80%2F2%5D%E4%B8%8A%E7%9A%84%E5%80%BC%E5%9F%9F)
y=2sin^2x-sinxcosx+3cos^2x求最小正周期,单调增区间,在[0,π/2]上的值域
y=2sin^2x-sinxcosx+3cos^2x求最小正周期,单调增区间,在[0,π/2]上的值域
y=2sin^2x-sinxcosx+3cos^2x求最小正周期,单调增区间,在[0,π/2]上的值域
y=2(sinx)^2-sinxcosx+3(cosx)^2
=2-sin2x/2+(cosx)^2=2-sin2x/2+cos2x/2+1/2
=5/2+(√2/2)cos(2x+π/4)
π+2kπ
函数y=sinxcosx-3sin^2(x)的最大值
y=(cos^2x)/(sinxcosx-sin^2x),(0
求y=sin^2x+2sinxcosx的周期
y=sin^2x+2sinxcosx的值域
y=sin^2x-sinxcosx+1/2的值域
求y=sin^2(x)-sinxcosx+2的值域
求y=sin平方x+2sinxcosx的周期
求y=sinxcosx+sin^2x,0
y=1/2cos^2x+sinxcosx+3/2sin^2x 求单调区间
y=2sin^2x-sinxcosx+3cos^2x 求值域
y=sin'2x+根号3sinxcosx+2cos'2x求值域和周期
y=sin^2x+2sinxcosx+3cos^2x的值域?
y=sin^2x-根号3sinxcosx-cos^2x化简
y=1/2cos²x+sinxcosx+3/2sin²x 求化简详程.
y=sin^2x+sinxcosx+3cos^2x的最值
y=sin^2X+2sinXcosX+3COS^X谢谢了,
y=sin^2x+3sinxcosx+5cos^2x值域
函数y=sin²x+2sinxcosx-3cos²x求周期?求最大值?