y=(x^2+1)ln(x^2+1),求dy

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y=(x^2+1)ln(x^2+1),求dy
y=(x^2+1)ln(x^2+1),求dy

y=(x^2+1)ln(x^2+1),求dy
dy=ln(x²+1)d(x²+1)+(x²+1)dln(x²+1)
=ln(x²+1)*2xdx+(x²+1)*1/(x²+1)*d(x²+1)
=2xln(x²+1)dx+2xdx
=[2xln(x²+1)+2x]dx

y=(x^2+1)ln(x^2+1)
dy=d(x^2+1)ln(x^2+1)dx+(x^2+1)d(ln(x^2+1))
=ln(x^2+1)*d(x^2)+(x^2+1)*1/(x^2+1) * d(x^2)
=(2xln(x^2+1)+2x)dx

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