作业帮已知集合M={x|1/2＜x≤6},不等式(x+m)/(2x-1)＞1.已知集合M={x|1/2＜x≤6},不等式(x+m)/(2x-1)＞1的解集是P,若P⊆M,则实数m的取值范围是( ).A.[-1/2,5] B.[-3,-1/2] C.[-3,5] D.[-3,-1/2)∪(-1/2,5]
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![已知集合M={x|1/2＜x≤6},不等式(x+m)/(2x-1)＞1.已知集合M={x|1/2＜x≤6},不等式(x+m)/(2x-1)＞1的解集是P,若P⊆M,则实数m的取值范围是( ).A.[-1/2,5] B.[-3,-1/2] C.[-3,5] D.[-3,-1/2)∪(-1/2,5]](/uploads/image/z/7140508-52-8.jpg?t=%E5%B7%B2%E7%9F%A5%E9%9B%86%E5%90%88M%3D%7Bx%7C1%2F2%EF%BC%9Cx%E2%89%A46%7D%2C%E4%B8%8D%E7%AD%89%E5%BC%8F%28x%2Bm%29%2F%282x-1%29%EF%BC%9E1.%E5%B7%B2%E7%9F%A5%E9%9B%86%E5%90%88M%3D%7Bx%7C1%2F2%EF%BC%9Cx%E2%89%A46%7D%2C%E4%B8%8D%E7%AD%89%E5%BC%8F%28x%2Bm%29%2F%282x-1%29%EF%BC%9E1%E7%9A%84%E8%A7%A3%E9%9B%86%E6%98%AFP%2C%E8%8B%A5P%26%238838%3BM%2C%E5%88%99%E5%AE%9E%E6%95%B0m%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%E6%98%AF%28+%29.A.%5B-1%2F2%2C5%5D+B.%5B-3%2C-1%2F2%5D+C.%5B-3%2C5%5D+D.%5B-3%2C-1%2F2%29%E2%88%AA%28-1%2F2%2C5%5D)
已知集合M={x|1/2＜x≤6},不等式(x+m)/(2x-1)＞1.已知集合M={x|1/2＜x≤6},不等式(x+m)/(2x-1)＞1的解集是P,若P⊆M,则实数m的取值范围是( ).A.[-1/2,5] B.[-3,-1/2] C.[-3,5] D.[-3,-1/2)∪(-1/2,5]
已知集合M={x|1/2＜x≤6},不等式(x+m)/(2x-1)＞1.
已知集合M={x|1/2＜x≤6},不等式(x+m)/(2x-1)＞1的解集是P,若P⊆M,则实数m的取值范围是( ).
A.[-1/2,5] B.[-3,-1/2] C.[-3,5] D.[-3,-1/2)∪(-1/2,5]
已知集合M={x|1/2＜x≤6},不等式(x+m)/(2x-1)＞1.已知集合M={x|1/2＜x≤6},不等式(x+m)/(2x-1)＞1的解集是P,若P⊆M,则实数m的取值范围是( ).A.[-1/2,5] B.[-3,-1/2] C.[-3,5] D.[-3,-1/2)∪(-1/2,5]
C
由（x+m)/(2x-1) >1得（x+m)/(2x-1) －1>0,
通分化简得（-x+m+1)/(2x-1)>0 ,上式等价于：（x-m－1)(2x-1)