这个式子是怎么化简出来的x/(x^2+1)-y/(y^2+1)=[(x-y)(1-xy)]/[(x^2+1)(y^2+1)] 我算了很多次我只能化成[(x-y)(x^2+y^2+1)]/[(x^2+1)(y^2+1)] 而已

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这个式子是怎么化简出来的x/(x^2+1)-y/(y^2+1)=[(x-y)(1-xy)]/[(x^2+1)(y^2+1)]  我算了很多次我只能化成[(x-y)(x^2+y^2+1)]/[(x^2+1)(y^2+1)]  而已

这个式子是怎么化简出来的x/(x^2+1)-y/(y^2+1)=[(x-y)(1-xy)]/[(x^2+1)(y^2+1)] 我算了很多次我只能化成[(x-y)(x^2+y^2+1)]/[(x^2+1)(y^2+1)] 而已
这个式子是怎么化简出来的
x/(x^2+1)-y/(y^2+1)=[(x-y)(1-xy)]/[(x^2+1)(y^2+1)] 我算了很多次我只能化成[(x-y)(x^2+y^2+1)]/[(x^2+1)(y^2+1)] 而已

这个式子是怎么化简出来的x/(x^2+1)-y/(y^2+1)=[(x-y)(1-xy)]/[(x^2+1)(y^2+1)] 我算了很多次我只能化成[(x-y)(x^2+y^2+1)]/[(x^2+1)(y^2+1)] 而已
=[y^2*x+x-y-x^2*y]/[(x^2+1)(y^2+1)]
=[(x-y)+xy(y-x)}/[(x^2+1)(y^2+1)]
=[(x-y)-xy(x-y)]/[(x^2+1)(y^2+1)]
=[(x-y)(1-xy)]/[(x^2+1)(y^2+1)]