计算或化简:(1+x²-2x+1分之x²-1)÷1/x-1

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计算或化简:(1+x²-2x+1分之x²-1)÷1/x-1

计算或化简:(1+x²-2x+1分之x²-1)÷1/x-1
计算或化简:(1+x²-2x+1分之x²-1)÷1/x-1

计算或化简:(1+x²-2x+1分之x²-1)÷1/x-1
原式=[1+(x+1)(x-1)/(x-1)²]×(x-1)
=[1+(x+1)/(x-1)]×(x-1)
=1×(x-1)+(x+1)/(x-1)×(x-1)
=x-1+1
=x

{ 1 + (x^2-1)/(x^2-2x+1)} ÷ 1/(x-1)
= { 1 + (x+1)(x-1)/ (x-1)^2 × (x-1)
= { 1 + (x+1)/ (x-1) }× (x-1)
= (x-1) + (x+1)
=2x