(x*x-3)*(x*x-3)-x*(x*x-3)-2x*x 因式分解

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(x*x-3)*(x*x-3)-x*(x*x-3)-2x*x 因式分解

(x*x-3)*(x*x-3)-x*(x*x-3)-2x*x 因式分解
(x*x-3)*(x*x-3)-x*(x*x-3)-2x*x 因式分解

(x*x-3)*(x*x-3)-x*(x*x-3)-2x*x 因式分解
(x²-3)²-x(x²-3)-2x²
=[(x²-3)+x][(x²-3)-2x]
=(x²+x-3)(x²-2x-3)
=(x²+x-3)(x+1)(x-3)

答：
(x²-3)(x²-3)-x(x²-3)-2x²
利用十字相乘法：
x²-3 -2x
*
x²-3 x
原式分解为：
(x²-3)(x²-3)-x(x²-3)-2x²
=(x²-3-2x)(x²-3+x)
=(x-3)(x+1)(x²+x-3)

(x*x-3)*(x*x-3)-x*(x*x-3)-2x*x
=(x^2-3)*(x^2-3)-x(x^2-3)-2x^2
=[(x^2-3)-2x]*[(x^2-3)+x]
=(x^2-3-2x)*(x^2-3+x)
=(x^2-2x-3)*(x^2+x-3)
=(x-3)*(x+1)*(x^2+x-3)

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