因式分解:(1)4(x-2)-2(2-x) (2)x^2(m-1)^2-4(1-m)^2 (3)-8x^2n+2y^n+2+12x^n+1y^2n+3(4)-m^2 n(x-y)^n+mn^2 (x-y)^n+1急急急急急急急,过程 (3)-8x^2n+2 y^n+2+12x^n+1 y^2n+3会几个打几个

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/12 02:11:48
因式分解:(1)4(x-2)-2(2-x) (2)x^2(m-1)^2-4(1-m)^2 (3)-8x^2n+2y^n+2+12x^n+1y^2n+3(4)-m^2 n(x-y)^n+mn^2 (x-y)^n+1急急急急急急急,过程 (3)-8x^2n+2 y^n+2+12x^n+1 y^2n+3会几个打几个

因式分解:(1)4(x-2)-2(2-x) (2)x^2(m-1)^2-4(1-m)^2 (3)-8x^2n+2y^n+2+12x^n+1y^2n+3(4)-m^2 n(x-y)^n+mn^2 (x-y)^n+1急急急急急急急,过程 (3)-8x^2n+2 y^n+2+12x^n+1 y^2n+3会几个打几个
因式分解:(1)4(x-2)-2(2-x) (2)x^2(m-1)^2-4(1-m)^2 (3)-8x^2n+2y^n+2+12x^n+1y^2n+3
(4)-m^2 n(x-y)^n+mn^2 (x-y)^n+1
急急急急急急急,过程 (3)-8x^2n+2 y^n+2+12x^n+1 y^2n+3
会几个打几个

因式分解:(1)4(x-2)-2(2-x) (2)x^2(m-1)^2-4(1-m)^2 (3)-8x^2n+2y^n+2+12x^n+1y^2n+3(4)-m^2 n(x-y)^n+mn^2 (x-y)^n+1急急急急急急急,过程 (3)-8x^2n+2 y^n+2+12x^n+1 y^2n+3会几个打几个
不好意思啊,我只会前两题,你另寻高人吧
(1)4(x-2)-2(2-x)
原式=4(x-2)+2(x-2)
=(4+2)(x-2)
=6(x-2)
(2)x^2(m-1)^2-4(1-m)^2
原式=(m-1)^2(x^2-4)
=(m-1)^2(x+2)(x-2)

一题 4(x-2)-2(2-x)
=4(x-2)+2(x-2)
=6(x-2)
二题 x^2(m-1)^2-4(1-m)^2
=x^2(m-1)^2-4(m-1)^2
=(x^2-4)(m-1)^2
=(x+2)(x-2)(m-1)^2

4(x-2)-2(2-x) =4(x-2)+2(x-2)
=(x-2)(4+2)
=6(x+2)
x^2(m-1)^2-4(1-m)^2=x^2(m-1)^2-4(m-1)^2
=(m-1)^2(x^2-4)
=(m-1)^2(x+2)(x-2)
-8x^2n+2y^n+2+12x^n+1y^2n+3可能题目错了

纠正楼上第一题(1)4(x-2)+2(x-2)=6(x-2)
其他正解

4(x-2)-2(2-x)
=4x-8-4+2x
=6x-12